√18 + √2>3√2+1,х≥0
3√2х+√2>3√2+1
3√2х>3√2+1-√2
3√2х>2√2+1
√2х>2√2/3+1/3
√2х>2√2+1/3
2х>(2√2+1)^2/9
2х>8+4√2+1/9
2х>9+4√2/9
х>9+4√2/18,х≥0
х=[9+4√2/18,+бесконечность
