1)3(3х+5)<2(2х+3)
9х+15<4х+6
9х-4х<6-15
5х<-9
Х<-9/5
2)2(х-2)>3(х-3)
2х-4>2х-9
2х-3х>4-9
-х>-5
х>5
ответ <-бесконечности;-9/5
х ≤ -1,8
Объяснение:
(3х+5)/2 ≤ (2х+3)/3, ×6 3(3х+5) ≤ 2(2х+3), 9х+15≤ 4х+6,
(х-2)/3 >(х-3)/2 ×6 2(х-2) >3(х-3) 2х-4 >3х-9
5х ≤ -9, х ≤ -9/5, ⇒ х ≤ -1,8
5 > х х< 5
