baharaliyeva
17.04.2021 00:24

, ОЧЕНЬ , ДАЮ (cos2y-y²cosx)dx=2(xsin2y+ysinx)dy

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Пиирмвп
26.01.2023 02:02

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Ответ:
кисюня011088
07.10.2021 14:12

Смотрите.

1) Обозначаем t — сколько времени они шли в первый день, тогда (t-1) — сколько во второй.

2) Теперь следующее соотношение — про 6 километров. Пускай в первый день они км, а во второй день — s2, тогда нам дано:

s1-s2=6.

3) Вспоминая, что расстояние=время*скорость (s=v*t), подставляем в эту формулу вместо s1 и s2:

(3,5*t)-(3*(t-1))=6.

Упрощаем:

3,5t-3t+3=6;

0,5t=3;

t=6.

ответ: Таким образом, в первый день они шли 6 часов. Во второй день — 6-1=5 (часов во второй день — 3*5 = 15 (км)

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