2^(sin2x/(cos2x-1))=2^(-sqrt(3))
sin2x/(cos2x-1)=-sqrt(3)
cos2x-1=cos^2x-sin^2x-sin^2x-cos^2x=-2sin^2x
2sinxcosx/-2sin^2x=-ctgx
-ctgx=-sqrt(3)
ctgx=sqrt(3)
x=П/6+Пk
