дано
Ba(NO3)2
W(Ba) - ?
W(N) - ?
W(O) - ?
M(Ba(NO3)2) = 137 + ( 14+16*3)*2 = 261 g/mol
W(Ba) = 137 / 261 * 100% = 52.49%
W(N)) = 14*2 / 261 * 100% = 10.73 %
W(O) = 16*6 / 261 * 100% = 36.78%
Объяснение:
