x²+bx+c = (x-x(1))*(x-x(2))
х(1) = -4
х(2) = -3
(х+3)(х+4) = х²+4х +3х +12 = х²+7х+12
x₁ = - 4 x₂ = - 3
x² + bx + c = 0
c = x₁ * x₂ = (- 4 ) * ( - 3) = 12
b = - (x₁ + x₂) = - ( - 4 - 3) = 7
ответ : x² + 7x + 12 = 0
