Решение:log _1/3 (5-2x) = - 3ОДЗ: 5 - 2х > 0, х < 2,5log _1/3 (5-2x) = log_1/3 (1/3)^(-3)log _1/3 (5-2x) = log_1/3 3^3log _1/3 (5-2x) = log_1/3 275 - 2х = 27- 2х = 27 - 5- 2х = 22х = 22 : (-2)х = - 11ответ: - 11.
