Пож-та, 2 примера 1) (5а-3с)(5а+-а)(7с+а) 2.) (4b+10c)(10c-4b)+(-5с+2b)(5c+2b) - вопрос №78010222153572410104525 от dzanhutovaiman 13.04.2023 06:33

Question

Алгебра: Пож-та, 2 примера 1) (5а-3с)(5а+-а)(7с+а) 2.) (4b+10c)(10c-4b)+(-5с+2b)(5c+2b)

dzanhutovaiman · Answer

(5а-3с)(5а+3с)-(7c-а)(7с+а)=(5а)²-(3с)²- ((7c)²-(а)²)=25a²-9c²-49c²+a²=

= 26a²-58c²

(4b+10c)(10c-4b)+(-5с+2b)(5c+2b)=(10c)²-(4b)²+((2b)²- (5с)²) =

=100c²-16b²+4b²-25c²=75c²-12b²