Народ! /x2-y2 - 3/x-y при x= -2/3 y= 3/4. заранее - вопрос №76310332232334 от mchizhevskayap010bm 11.05.2020 12:16

Question

Алгебра: Народ! /x2-y2 - 3/x-y при x= -2/3 y= 3/4. заранее

mchizhevskayap010bm · Answer

= 6х-3(х+у) / (х-у)(х+у) = 6х-3х-3у / (х-у)(х+у) = 3х-3у / (х-у)(х+у) = = 3(х-у) / (х-у)(х+у) = 3 / х+у = 3 / (-2/3+3/4) = 3 / (-8/12+9/12) = = 3 / 1/12 = 3*12 = 36...