(y/2+3y-5y/3y-2): 4y^3+4y^2/9y^2-12y+4 выполнить действие

1)y/(2+3y)-5y)/(3y-2)=(3y²-2y-10y-15y²)/(2+3y)(3y-2)=
=(-12y²-12y)/(2+3y)(3y-2)=-12y(y+1)/(2+3y)(3y-2)
2)-12y(y+1)/(2+3y)(3y-2) * (3y-2)²/4y²(y+1)=-3(3y-2)/y(2+3y)=
=3(2-3y)/y(2+3y)