Решите уравнение, (x^2-3x-1)^2=(x^2-4x+1)^2 - вопрос №575510023122412 от kristinakissa1 22.12.2021 00:21

Question

Алгебра: Решите уравнение, (x^2-3x-1)^2=(x^2-4x+1)^2

kristinakissa1 · Answer

(x²-3x-1)² -(x²-4x+1)² =0(x²-3x-1 -(x²-4x+1))(x²-3x-1 +(x²-4x+1)) =0(x²-3x-1-x²+4x-1)(x²-3x-1+x²-4x+1) =0(x -2)(2x² -7x) =0x(x -2)(2x -7) =0x =0,x -2 =0, x =22x -7 =0, 2x =7, x =7/2 =3.5ответ: x =0, x =2, x =3.5...