Найдите корни уравнения 2х-5x^2=0 4m^2-3m=0 y^2-2y-8=2y-8 - вопрос №4562848252042302282832767 от anncopper 19.11.2020 16:03

Question

Алгебра: Найдите корни уравнения 2х-5x^2=0 4m^2-3m=0 y^2-2y-8=2y-8 3u^2+7=6u+7

anncopper · Answer

2x - 5x^2 = 0
x ( 2 - 5x) = 0
x = 0
2 - 5x = 0 ==> 5x = 2 ==> x = 2/5 = 0.4

4m^2 - 3m = 0
m (4m - 3) = 0
m = 0
4m - 3 = 0 ==> 4m = 3 ==> m = 3/4 = 0.75

y^2 - 2y - 8 = 2y - 8
y^2 - 2y - 2y = 0
y^2 - 4y = 0
y ( y - 4) = 0
y = 0;
y - 4 = 0 ==> y = 4

3u^2 + 7 = 6u + 7
3u^2 - 6u = 0
u^2 - 2u = 0
u ( u - 2) = 0
u = 0
u - 2 = 0 ==> u = 2