Выражение: 1) (2m+3)(4m²-6m+9) 3) (m+2a)(m²-2am+4a² - вопрос №2239699123469322451644 от nikiraspru 20.10.2022 13:02

Question

Алгебра: Выражение: 1) (2m+3)(4m²-6m+9) 3) (m+2a)(m²-2am+4a² 5) (16y²+4yz²+z⁴)(4y-z²) 7) (4z⁶-2x³z³+x⁶)(2z³+x³)

nikiraspru · Answer

(2m+3)(4m²-6m+9)= (2m+3)(2m-3)(2m-3)=(4m²-9)(2m-3)

(m+2a)(m²-2am+4a²)= (m+2a)(m-2a)(m-2a)=(m-2a)(m²-4a²)

(16y²+4yz²+z⁴)(4y-z²) = (4y-z²)(4y+z²)(4y+z²)= (16y²-z⁴)(4y+z²)

(4z⁶-2x³z³+x⁶)(2z³+x³)= (2z³-x³)(2z³-x³)(2z³+x³)= (4z⁶-x⁶)(2z³-x³)