A Представьте в виде многочленов (32.1-32.2):
32.1. 1) (m - 3)2;
2) (x+5)2; 3) (6 + y);
5) (4 +d)2; 6) (p+q)2; 7) (z? - у);
32.10
4) (b - 9;
8) (а + 1.
200​

32.1.

1) (m - 3)^2

To find the square of a binomial, we can use the formula (a - b)^2 = a^2 - 2ab + b^2. In this case, a = m and b = 3.

So, (m - 3)^2 = m^2 - 2m(3) + (3)^2
= m^2 - 6m + 9

2) (x + 5)^2

Using the same formula, where a = x and b = 5:

(x + 5)^2 = x^2 + 2x(5) + (5)^2
= x^2 + 10x + 25

3) (6 + y)

This is already in the form of a binomial (6 + y). There's no need to further simplify it.

5) (4 + d)^2

Using the same formula, where a = 4 and b = d:

(4 + d)^2 = (4)^2 + 2(4)(d) + d^2
= 16 + 8d + d^2

6) (p + q)^2

Using the same formula, where a = p and b = q:

(p + q)^2 = p^2 + 2p(q) + (q)^2
= p^2 + 2pq + q^2

7) (z? - у)

It seems that there is a typo in the equation as there is a question mark instead of a specific symbol. Please provide the correct equation for a proper answer.

32.10

4) (b - 9)

This is already in the form of a binomial (b - 9). There's no need to further simplify it.

8) (а + 1)

This is already in the form of a binomial (a + 1). There's no need to further simplify it.