х)(х+1,2)+1,8х+х²=02)0,49х²-3х-(0,7х+2)(0,7х-2)=03)(1,6х+1)(1-1,6х)-64х(1-0,04х)=0 - вопрос №16830342121802049307207203161116641 от alexcozearschi 21.12.2022 16:15

Question

Алгебра: х)(х+1,2)+1,8х+х²=02)0,49х²-3х-(0,7х+2)(0,7х-2)=03)(1,6х+1)(1-1,6х)-64х(1-0,04х)=0​

alexcozearschi · Answer

х= -0,8x = 4/3х=1/64Объяснение:1) 1,2х+1,44-х²-1,2х+1,8х+х²=0 1,44+1,8х=0 1,8х=-1,44 х= -0,82) 0,49х²-3х-(0,7х+2)(0,7х-2)=0    -3x +4 = 0    -3x = -4    x = 4/33) (1,6х+1)(1-1,6х)-64х(1-0,04х)=0 1,6х-2,56х²+1-1,6х-64х+2,56х²=0 1-64х=0 -64х=-1 х=1/64...

х)(х+1,2)+1,8х+х²=02)0,49х²-3х-(0,7х+2)(0,7х-2)=03)(1,6х+1)(1-1,6х)-64х(1-0,04х)=0​

х)(х+1,2)+1,8х+х²=0
2)0,49х²-3х-(0,7х+2)(0,7х-2)=0
3)(1,6х+1)(1-1,6х)-64х(1-0,04х)=0