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(m+1)!/(m-1)!=30,
(m+1)!=1*2*...*(m-2)*(m-1)*m*(m+1),
(m-1)!=1*2*...*(m-2)*(m-1),
m(m+1)=30,
m^2+m-30=0,
по теореме Виета
m_1=-6<0, m_2=5;
m=5;
(k+1)!/k!=12,
(k+1)!/k!=1*2*...*(k-1)*k*(k+1)/(1*2*...*(k-1)*k)=k+1,
k+1=12,
k=11.
