Преобразуйте уравнение (4x - 1)(3x + 10) - (x - 1)(4x + 6) = 33x + 106 ах2 + + с =0 и укажите старший коэффициент, второй коэффициент и свободный член​

X^2+3x+sqrt5=0
(x1*x2)=корень(5) - по т.виетта
(x1+x2)=-3 - по т.виетта

а)(x1*x2)^2=(корень(5))^2=5
б)x1^2+x2^2=(x1+x2)^2-2*x1*x2=9-2*корень(5)~ 4,527864

в)x1:x2^2+x2:x1^2=(x1^3+x2^3)/(x1*x2)^2
(x1^3+x2^3)=(x1+x2)(x1^2-x1x2+x2^2)
x1:x2^2+x2:x1^2=(x1^3+x2^3)/(x1*x2)^2=(x1+x2)(x1^2-x1x2+x2^2)/(x1*x2)^2=
=(-3)(9-2*корень(5)-корень(5))/(корень(5))^2=
=(-3)*(9-3*корень(5))/5 ~ -1,37508

г)x1^4+x2^4=(x1^2+x2^2)^2-2*(x1*x2)^2=(9-2*корень(5))^2-2*(корень(5))^2=
=81+4*5-10-2*9*2*корень(5)=91-36*корень(5)~10,50155281

1)sin20⁰cos10⁰+cos20⁰sin10⁰=
=1/2[sin(20⁰+10⁰)+sin(20⁰-10⁰)]+1/2[sin(10⁰+20⁰)+sin(10⁰-20⁰)]=
=1/2[sin30⁰+sin10⁰]+1/2[sin30⁰+sin(-10⁰)]=sin30⁰+1/2sin10⁰-1/2sin10⁰=
=sin30⁰=1/2;
2)sinπ/5cos4π/5+cosπ/5sin4π/5=
=1/2[sin(π/5+4π/5)+sin(π/5-4π/5)]+1/2[sin(4π/5+π/5)+sin(4π/5-π/5)]=
=1/2[sinπ+sin(-3π/5)]+1/2[sinπ+sin(3π/5]=
=sinπ-1/2sin(3π/5)+1/2sin(3π/5)=
=sinπ=0;
3)cos80⁰cos10⁰+sin80⁰cos10⁰=
=1/2[cos(80⁰-10⁰)+cos(80⁰+10)⁰]+1/2[sin(80⁰+10⁰)+sin(80⁰-10⁰)]=
=1/2[cos70⁰+cos90⁰]+1/2[sin90⁰+sin70⁰]=
=1/2[cos70⁰+0]+1/2[1+sin70⁰]=1/2cos70⁰+1/2sin70⁰+1/2;
4)cos3π/8sinπ/8+cosπ/8sin3π/8=
=1/2[sin(π/8+3π/8)+sin(π/8-3π/8)]+1/2[sin(3π/8+π/8)+sin(3π/8-π/8)]=
=1/2[sin(π/2)+sin(-π/4)]+1/2[sin(π/2)+sin(π/4)]=
=sin(π/2)-1/2sin(π/4)+1/2sin(π/4)=sin(π/2)=1;