0.1;0.2;0.4b1=0.1q=b2/b1=0.2/0.1=2а)Sn=b1*(q^n-1)/q-1 0.1*(2^n-1)/(2-1) = 51.12^n-1=5112^n=512n=9б) 0.1*(2^n-1)/(2-1)>100.1*(2^n-1)>102^n-1>1002^n>101n>60.1*(2^n-1)/(2-1)<402^n-1<4002^n<401n<8 n=7