5
Объяснение:
6(y+1)^2+2(y-1)(y^2+y+1)-2(y+1)^3=32
6(y+1)²+2(y³-1)-2(y+1)³=32
6(y²+2y+1)+2y³-2-2(y³+3y²+3y+1)=32
6y²+12y+6+2y³-2-2y³-6y²-6y-2=32
6y+2=32
6y+2-32=0
6y-30=0
6y=30
y=5
