4^x*4^x-3^x*4^x-2*3^x*3^x<=0
(4/3)^x=y y>0
(y^2-y-2)/y<=0
(y+1)(y-2)/y<=0
0<y<=2
(4/3)^x<=2
x<=1/log(2)(4/3) логарифм по основанию 2
