решить

1) f(x)=x^2/(x-3)^2

2) f(x)=2x^3/x^2-1

3) f(x)=x^2-6x+9/(x-1)^2

4) f(x)=x^2/x^3-1

Question

Алгебра: решить 1) f(x)=x^2/(x-3)^2 2) f(x)=2x^3/x^2-1 3) f(x)=x^2-6x+9/(x-1)^2 4) f(x)=x^2/x^3-1

anonimus8310 · Answer

1)f(x)=x^2/(x-3)^20=x^2/(x-3)^2x=02)f(x)=2x^3/x^2-1 0=2x^3/x^2-1x=1 дробь 23)f(x)=x^2-6x+9/(x-1)^2f(0)=0^2-6x•0+9/(0-1)^2f(0)=0^2-6•0+9/(-1)^2f(0)=0-0+9/1(f)0=94)f(x)=x^2/x^3-10=x^2/x^3-1x=1...