1) (5c + 3)(-c + 2) 2) (3t- 1)(2t + 1) 3) (3x + 1)^2

4) (w + 2)(w^2 + 2w - 1) 5) (2w - 1)(w^2 + w + 1)

Question

Алгебра: 1) (5c + 3)(-c + 2) 2) (3t- 1)(2t + 1) 3) (3x + 1)^2 4) (w + 2)(w^2 + 2w - 1) 5) (2w - 1)(w^2 + w + 1)

osazienko · Answer

1) -5c*c+5c*2-3c+3*2=-5c^2+10c-3c+6=-5c+7c+6
2) 3t*2t+3t-2t-1=6t^2+3t-2t-1=6t^2+t-1
3) (3x)^2+2*3x*1+1^2=9x^2+6x+1
4) w*(w^2+2w-1)+2(w^2+2w-1)=w^3+2w^2-w+2w^2+4w-2=w^3+4w^2+3w-2
5) 2w*(w^2+w+1)-1(w^2+w+1)=2w^3+2w^2+2w-w^2-w-1=2w^3+w^2+w-1