Объяснение:
f(x)=√(5+2x-3x³) x₀=1 f'(x₀)=?
f'(x)=(√(5+2x-3x³))'=(5+2x-3x³)'/(2*√(5+2x-3x³))=(2-9x²)/(2*√(5+2x-3x³)).
f'(1)=(2-9*1²)/(2*√(5+2*1-3*1³))=(2-9)/(2*√(5+2-3))=-7/(2*√4)=-7/4=-1,75.
ответ: f'(1)=-1,75.
