2) (0,3b^3 + x)(0,3b^3 – x); 4) (21d^2 - k^3)(21d^2 - вопрос №10501197203303342123212361946 от butchenko02 23.04.2022 09:16

Question

Алгебра: 2) (0,3b^3 + x)(0,3b^3 – x); 4) (21d^2 - k^3)(21d^2 +k^3); 6) (1,9c^4+ 6d)(6d-1,9c^4); ​ 50

butchenko02 · Answer

(0,3b³)²-x² = 0.09b⁶-x²(21d²)²-(k³)² = 441d⁴-k⁶(1,9c^4+ 6d)(6d-1,9c^4) = (6d-1,9c^4)(6d+1,9c^4) = (6d)²-(1.9c⁴)² = 36d²-3.61c⁸...

2) (0,3b^3 + x)(0,3b^3 – x); 4) (21d^2 - k^3)(21d^2 +k^3); 6) (1,9c^4+ 6d)(6d-1,9c^4); ​ 50