ответ: log3 81 : log0.5 2 * log5 125 = =>
пошаговое объяснение: __ log3 81 = log3 (3^4) =4
__ log(0,5) 2 = log(2^(-1)) 2 = 1/(-1) * log2 2 = -1
__ log5 125 = log5 5^3 = 3
=>
= 4 : (-1) * 3 = -4/3
