Решить дроби. 23: (6целыз 5/17+1целая 12/17) - (4 целых 2/5. - 2 целых 3/5) : 5 =

23/ ( 6 5/17 + 1 12/17) – (4 2/5 – 2 3/5) / 5 = 23 / (107/17 + 29/17) – (22/5 – 13/5) / 5 = 23 / ((107 + 29) / 17)) – ((22 – 13) / 5) / 5 = 23 / 8 – 9/5 /5 = 23/8 – 9 = 23/8 – 72/8 = (23 – 72) / 8 = - 49/8 = -6 целых 1/8