1)7/8=х/96 2)2+5/5=4/9 3)4(х-3)=х+6 4)4-6(х+2)=3-5х - вопрос №9190372178962255493436446235503833208 от okru24057p00ymy 10.09.2020 07:21

Question

Математика: ﻿1)7/8=х/96 2)2+5/5=4/9 3)4(х-3)=х+6 4)4-6(х+2)=3-5х 5)0,3(8-3у)=3,2-0,8(у-7)

okru24057p00ymy · Answer

1)7/8=Х/968*x = 7*968x = 672x = 672 : 8x = 842)2+5/5=4/93)4(Х-3)=Х+64x - 12 = x + 64x - x = 6 + 123x = 18x = 18 : 3x = 64)4-6(Х+2)=3-5Х4 - 6x - 12 = 3 - 5x-8 - 6x = 3 - 5x6x - 5x = -8 - 3x = -115)0,3(8-3У)=3,2-0,8(У-7)2,4 - 0,9y = 3,2 - 0,8y + 5,62,4 - 0,9y = 8,8 - 0,8y 0,9y - 0,8y = 2,4 - 8,80,1y = -6,4y = -6,4 : 0,1y = -64...

﻿1)7/8=х/96 2)2+5/5=4/9 3)4(х-3)=х+6 4)4-6(х+2)=3-5х 5)0,3(8-3у)=3,2-0,8(у-7)

1)7/8=х/96 2)2+5/5=4/9 3)4(х-3)=х+6 4)4-6(х+2)=3-5х 5)0,3(8-3у)=3,2-0,8(у-7)