1\dfrac{33}{35}1
35
33
Пошаговое объяснение:
3\dfrac{1}{7}-18\dfrac{1}{5}:15\dfrac{1}{6}=\dfrac{3 \cdot 7+1}{7}-\dfrac{18 \cdot 5+1}{5}:\dfrac{15 \cdot 6+1}{6}=\dfrac{22}{7}-\dfrac{91}{5}:\dfrac{91}{6}=\dfrac{22}{7}-\dfrac{91}{5} \cdot3
7
1
−18
5
1
:15
6
1
=
7
3⋅7+1
−
5
18⋅5+1
:
6
15⋅6+1
=
7
22
−
5
91
:
6
91
=
7
22
−
5
91
⋅
\cdot \dfrac{6}{91}=\dfrac{22}{7}-\dfrac{6}{5}=\dfrac{22 \cdot 5-6 \cdot 7}{7 \cdot 5}=\dfrac{110-42}{35}=\dfrac{68}{35}=1\dfrac{33}{35};⋅
91
6
=
7
22
−
5
6
=
7⋅5
22⋅5−6⋅7
=
35
110−42
=
35
68
=1
35
33
;
