ΔABC и ΔCBH подобны по 2 углам
СH/AC=CB/AB
tgA=CB/AC
5/12=CB/2.6
CB=2.6*5/12=13/12
AB^2=AC^2+CB^2
AB^2=2.6^2+(13/12)^2=7.93
AB=2.81
CH/AC=CB/AB
CH=AC*CB/AB=2.6*13/(12*2.81)=33.8/33.72=1 примерно
