6целых 13/24 - ((14 целых 7/24 - 10 целых 31/48) - - вопрос №840820261324147241031482341 от husanov18p06h9l 19.03.2023 04:11

Question

Математика: 6целых 13/24 - ((14 целых 7/24 - 10 целых 31/48) - (2 целых 3/4 - 1 целых 7/12)) - 1целых 1/16= по действиям

husanov18p06h9l · Answer

6 13/24 - ((14 7/24 - 10 31/48) - (2 3/4 - 1 7/12)) - 1 1/16= 6 26/48 -((14 14/48 - 10 31/48) - (2 36/48 - 1 28/48) - 1 3/48 = 6 26/48 - ( 3 31/48 - 1 8/48) - 1 3/48 = 6 26/48 - 2 23/48 - 1 3/48 = 3
ответ: 3

1) 14 7/24 - 10 31/48 = 14 14/48 - 10 31/48 = 13 62/48 - 10 31/48 = 3 31/48
2) 2 3/4 - 1 7/12 = 2 9/12 - 1 7/12 = 1 2/12 = 1 1/6
3) 3 31/48 - 1 1/6 = 3 31/48 - 1 8/48 = 2 23/48
4) 6 13/24 - 2 23/48 = 6 26/48 - 2 23/48 = 4 3/48
5) 4 3/48 - 1 1/16 = 4 3/48 - 1 3/48 = 3
ответ: 3