(200+y)*3+500=1400. (y+50)*2=400-100. (3500-x)*2=1000. - вопрос №82448392003500140050240010035002100054001002 от kodir74 23.03.2021 15:14

Question

Математика: (200+y)*3+500=1400. (y+50)*2=400-100. (3500-x)*2=1000. x+5=(400-100): 2 зам все

kodir74 · Answer

(200+у)*3+500=1400600+3у+500=14003у+1100=14003у=1400-11003у=300у=300:3у=100(у+50)*2=400-1002у+100=3002у=300-1002у=200у=200:2у=100(3500-х)*2=10007000-2х=10002х=7000-10002х=6000х=6000:2х=3000х+5=(400-100):2х+5=300:2х+5=150х=150-5х=145...