99/10 : ( 79 3/16 - 1 1/12 - 77 1/2 + 2 19/48 - вопрос №776119699107931611127712219483741453645 от zejnabnasibova 31.05.2020 15:12

Question

Математика: 99/10 : ( 79 3/16 - 1 1/12 - 77 1/2 + 2 19/48 ) ×( 37 41/45 - 36 4/5) =

zejnabnasibova · Answer

9 9/10 ÷( 79 3/16 - 1 1/12 - 77 1/2 + 2 19/48 ) ×( 37 41/45 - 36 4/5) = 3 2/3
79 3/16-1 1/12=1267/16 - 13/12 =(1267 × 3 - 13 × 4)/48 = 3801/48 - 52/48 = 3749/48 = 78 5/48
78 5/48-77 1/2=3749/48 - 155/2 = (3749 × 1 - 155 × 24)/48 = 3749/48 - 3720/48 = 29/48
29/48+2 19/48=29/48 + 115/48 = 144/48 = 3
37 41/45-36 4/5=1706/45 - 184/5 = (1706 × 1 - 184 × 9)/45 = 1706/45 - 1656/45 = 50/45 = 10/9 = 1 1/9
9 9/10÷3=99/10 × 1/3 = 33/10 = 3 3/10
3 3/10 × 1 1/9 = 33/10 × 10/9 = 11/3 = 3 2/3