Вычислить. sin (11п/3) +tg585° - cos (19п/3) подробнее объясните решение

Sin(11π/3)+tg585°-cos(19π/3)=sin(12π/3-π/3)+tg(540°+45°)-cos(18π/3+π/3)=
=sin(4π-π/3)+tg(3.180°+45°)-cos(6π+π/3)=sin(-π/3)+tg45°-cos(π/3)=
=-sin(π/3)+1-cos(π/3)=(-√3)/2+1-1/2=1/2-√3/2=(1-√3)/2

(sin(x+2kπ)=sinx, tg(x+kπ)=tgx, cos(x+2kπ)=cosx, tg45°=1,cos(π/3)=1/2,
sin(π/3)=√3/2)