Log1/3(√3/7+2√10)+log√3(1+/√5+√2) please help - вопрос №775544313372103152 от vda200311 22.05.2020 11:54

Question

Математика: Log1/3(√3/7+2√10)+log√3(1+/√5+√2) please help

vda200311 · Answer

Log₁/₃(√3/(7+2*√10))+log√₃(1/(√5+√2))==log₃⁻¹(√3/(7+2*√10))+log₃¹/²(1/(√5+√2))==log₃(√3/(7+2*√10))⁻¹+log₃(1/(√5+√2)²)==log₃((7+2*√10)*1)/(√3*(√5+√2)²)==log₃(7+2√10)/(√3*((√5)²+2*√5*√2+(√2)²))==log₃(7+2√10)/(√3*(7+2*√10))==log₃(1/√3)=log₃3⁻¹/²=-1/2....