27 3/8-21 7/20 : (3 4/7- 1 23/28) - (1 47/65 - - вопрос №7550591273821720347123281476529130 от andrewlitvinov4 22.12.2020 22:47

Question

Математика: 27 3/8-21 7/20 : (3 4/7- 1 23/28) - (1 47/65 - 29/130)

andrewlitvinov4 · Answer

27³/₈-21⁷/₂₀ : (3⁴/₇- 1²³/₂₈) - (1⁴⁷/₆₅ - ²⁹/₁₃₀) = 13,675
3⁴/₇- 1²³/₂₈ = ²⁵/₇- ⁵¹/₂₈ = ²⁵ˣ⁴/₂₈ - ⁵¹/₂₈ = ¹⁰⁰/₂₈ - ⁵¹/₂₈ = ¹⁰⁰⁻⁵¹/₂₈ = ⁴⁹/₂₈ = ⁷/₄
21⁷/₂₀ : ⁷/₄= 21⁷/₂₀ : ⁷/₄ = ⁴²⁷/₂₀ × ⁴/₇= ⁴²⁷ˣ⁴/₂₀ₓ₇ = ⁶¹ˣ⁴/₂₀= ⁶¹/₅ = 12,2
27³/₈ - 12,2 = 27,375 - 12,2 = 15,175
1⁴⁷/₆₅ - ²⁹/₁₃₀ = ¹¹²/₆₅ - ²⁹/₁₃₀ = ¹¹²ˣ²/₁₃₀ - ²⁹/₁₃₀ = ²²⁴/₁₃₀ - ²⁹/₁₃₀ = ²²⁴⁻²⁹/₁₃₀ = ¹⁹⁵/₁₃₀ = 1,5
15,175 - 1,5 = 13,675