Решите систему уравнений: 3х+y=1 x+1/3 - y/5=2

J{3x+y=1
{x+1/3-(y/5)=2|*15
{3x+y=1|*3
{5x-3y=25
+{9x+3y=25
+{5x-3y=3
14x=28:14
x=2
3*2+y=1
y=1-6
y=-5

3x+y=1
x+1/3-y/5=2
 
y=1-3x
x-y/5=2-1/3

y=1-3x
(5x-y)/5=(6-1)/3

y=1-3x
(5x-(1-3x))/5=5/3

y=1-3x
(5x-1+3x)/5=5/3

y=1-3x
(8x-1)/5=5/3 |×15

y=1-3x
3×(8x-1)=5×5

y=1-3x
24x-3=25

y=1-3x
24x=28 | ÷24

y=1-3x
x=7/6

y=1-3×7/6
x=7/6

y=1-7/2
x=7/6

y=(2-7)/2
x=7/6

y=-5/2
x=7/6