Решите систему уравнения 3-(х-2)-4у=18 2х-3у+3=2(3х-у)

3-(х-2)-4у=18
2х-3у+3=2(3х-у)

3-x+2-4y=18;
2x-3y+3=6x-2y;

-x=18-2-3+4y;
2x-6x-3y+2y+3=0;

-x = 13+4y;
-4x-y+3=0;

4*(13+4y)  - y + 3 = 0;
52+16y-y+3=0;
15y = -55;
3y = -11;
y = -11/3;

x = -4y - 13;
x = 4 * 11/3 - 13;
x = 44/3 - 39/3;
x = 5/3;

x = 5/3; y = -11/3;