A)31/80+(3/16+39/80) б)2/45+(3/45+7/9) в)(3/7+5/14)+1/14 - вопрос №3958593318031639802453457937514114 от damirpro 03.01.2020 05:47

Question

Математика: A)31/80+(3/16+39/80) б)2/45+(3/45+7/9) в)(3/7+5/14)+1/14

damirpro · Answer

A) 31/80+(3/16+39/80)= 31/80+((15+39)/80)=31/80+54/80=85/80=17/16b) 2/45+(3/45+7/9)=2/45+(3/45+35/45)=2/45+38/45=40/45=8/9c)(3/7+5/14)+1/14=(6/14+5/14)+1/14=11/14+1/14=12/14=6/7...