1)(98221-8028)*100+98098= 2)(30000-400*253)): 125+16= - вопрос №369619919822180281009809823000040025312516350906412233086 от Sili12 26.01.2020 21:04

Question

Математика: 1)(98221-8028)*100+98098= 2)(30000-400*253)): 125+16= 3)5090*64-122330+8670=

Sili12 · Answer

1) (98221-8028)*100+98098=90193*100+98098=9019300+98098=9117398
2) (30000-400*253)):125+16=(30000-101200):125+16= - 71200:125+16= -569,6+16= -553,6
3) 5090*64-122330+8670=325760-122330+8670=203430+8670=212100