Где можно раскройте всё как решали по ! зарание 1) 4a + 3c – 3a – 4c; 2) 3(3k – c) – (3c - k); 3) 4(y – a) - 5(2a – y); 4) 10 – ( – (2x + 5) – 4). 1) 3y – ( - 4a) + 2y – 3a; 2) 3(14 – k) – 2(k + 2); 3) 13(a – y) - 12( – y + a); 4) 4 - 2x - (5 – (3x + 1) 4h – 8f + 2f – 12h; 2) 3h – (– 2 + h) - 12; 3) - (– 45k + 1) – 2(30k + 5); 4) x + 2 - (7x – 1 – (x +

1) 4a + 3c – 3a – 4c=a-c
 2) 3(3k – c) – (3c - k)=9k-3c-3c+k=10k-6c
 3) 4(y – a) - 5(2a – y)=4y-4a-10a+5y=9y-14a

4) 10 – ( – (2x + 5) – 4)=10-(-2x-5-4)=10+2x+5+4=19+2x

1) 3y – ( - 4a) + 2y – 3a=3y+4a+2y-3a=5y-a

2) 3(14 – k) – 2(k + 2)=42-3k-2k-4=38-5k
 3) 13(a – y) - 12( – y + a)=13a-13y+12y-12a=a-y

4) 4 - 2x - (5 – (3x + 2))=4-2x-(5-3x-2)=4-2x-5+3x+2=1+x


1) 4h – 8f + 2f – 12h=-8h-6f

2) 3h – (– 2 + h) - 12=3h+2-h-12=2h-10

3) - (– 45k + 1) – 2(30k + 5)=45k-1-60k-10=-15k-11
 4) x + 2 - (7x 
– 1 – (x + 2))=x+2-(7x-1-x-2)=x+2-7x+1+x+2=-5x+5

1) 4a + 3c – 3a – 4c = а-с
2) 3(3k – c) – (3c - k) = 9к-3с-3с+к= 10к-6с
3) 4(y – a) - 5(2a – y) = 4у-4а-10а+5у= 9у-14а
4) 10 – ( – (2x + 5) – 4) = 10-(2х-5)-4 = 10-2х+5+4 = 19+2х
1) 3y – ( - 4a) + 2y – 3a = 3у+4а+2у= 5у+4а
2) 3(14 – k) – 2(k + 2)= 42-3к-2к-2 = 40-5к
3) 13(a – y) - 12( – y + a) = 13а-13у+12у-а = 12а-у
4) 4 - 2x - (5 – (3x + 2)) = 4-2х-(5-3х-2) = 4-2х-5+3х+2 = 3х+1
1) 4h – 8f + 2f – 12h = -8н-6ф = 8н+6ф
2) 3h – (– 2 + h) - 12 = 3н+2-н-12 = 2н-10
3) - (– 45k + 1) – 2(30k + 5) = 45к-1-60к-10 = -15к-11 = 15к+11
4) x + 2 - (7x – 1 – (x + 2)) = х+2-7х+1+х+2 = -5х+5 = 5х-5