Как сможете 1) log3.2 (2-x) = log3.2 (3x+6) 2) log0.8 (1+2x) = log0.8 (4x-10) 3) log2 (x-6)+ log2 (x-8) = 3 4) log8 (x-2) - log8 (x-3) = 1/3 1) lg (5-x) = 1/3lg (35-x^3) 2) log2 x-5/x+5 + log2 (x+5) = 0 3) log2 (3x-6) - 1 = log2 (9x-19) 1)log7 (x-2) + log7 (x+2) = log7 (4x+41) 2) log4 (x+1) - log4 (1-x) = log4 (2x+3) 3) log4 (x+3) - log4 (x-1) = 2 - log4 8 4) lg (x-1) + lg (x+1) = 3lg2 + lg (x-2) 1) 2 log3 (x-2) + log3 (x-4)^2 = 0 2) 2lgx - lg4 + lg (5-x^2) = 0 3) lg [x(x+9)] + lg x+9/x = 0