Тупой решить: 5sin 360° + cos360°
tg 0° + sin 180° – cos0°
ctg60° – tg 30°
sin 120° – cos60°
sin 135° + cos 135°
tg 120° : ctg 150°

5sin 360° + cos360° = 5•0+1 = 1
tg 0° + sin 180° – cos0° = 0+0-1 = -1
ctg60° – tg 30° = √3/3 - √3/3 = 0
sin 120° – cos60° = √3/2 - 1/2 = (√3-1)/2
sin 135° + cos 135° = √2/2 - √2/2 = 0
tg 120° : ctg 150° = -√3 /-√3 = -1