1. а) f(x)= 1/х^3+x^2
f'(x) = d/dx* ( (1/x^3)+x^2)
f'(x) = d/dx* (1/x^3) + d/dx * (x^2)
f'(x) = -3x^2/((x^3)^2)+2x
f'(x) = -3+2x^5/x^4
б) f(x) = (x^2+1)*(x^2-1)
f'(x) = d/dx* ((x^2+1)* (x^2-1))
f'(x) = d/dx *(x^4 -1)
f'(x) = 4x^3-0
f'(x) =4x^3.
Пошаговое объяснение:
