33.8. 1) (x + 1)8 - 4x = 5 + x(x + 3); 2) (1 - y) + 8y = 7 + y²(3-y);
3) (x + 1)' + (x - 1)3 – 2x3 = 12;
4) (1 + y) + (1 - y): – 6y2 = 3y - 1.

Question

Математика: 33.8. 1) (x + 1)8 - 4x = 5 + x(x + 3); 2) (1 - y) + 8y = 7 + y²(3-y);3) (x + 1) + (x - 1)3 – 2x3 = 12;4) (1 + y) + (1 - y): – 6y2 = 3y - 1.​

nasti2125 · Answer

(х+1)8-4х=5+х(х+3)8х+8-4х=5+х²+3хх-х²=-3...

33.8. 1) (x + 1)8 - 4x = 5 + x(x + 3); 2) (1 - y) + 8y = 7 + y²(3-y);3) (x + 1)' + (x - 1)3 – 2x3 = 12;4) (1 + y) + (1 - y): – 6y2 = 3y - 1.​

33.8. 1) (x + 1)8 - 4x = 5 + x(x + 3); 2) (1 - y) + 8y = 7 + y²(3-y);
3) (x + 1)' + (x - 1)3 – 2x3 = 12;
4) (1 + y) + (1 - y): – 6y2 = 3y - 1.