Пошаговое объяснение:
1) у₁ =(x+2)², y₂ = 0, x = 0
рис 1
2) у₁ =2x-x², y₂ = 0
3) у₁ = x²+1, e =0, x = 0, x=2
4) y₁=1+2sinx, y₂ = 0, x=0, x= π/2
![\displaystyle S=\int\limits^0_{-2} {(x+2)^2} \, dx =\left[\begin{array}{ccc}u=x+2\quad du=dx\\u_1=2-2=0\hfill\\u_2=2+0=2\hfill\end{array}\right] =\int\limits^2_0 {u^2} \, du =\frac{u^3}{3} \bigg |_0^2=\frac{8}{3}](/tpl/images/1787/8606/cd23b.png)
