Выражение: (1-〖cos〗^2 α)/(〖sin〗^2 α)+1/(〖sin〗^2 α*(1+〖tg〗^2 - вопрос №1702641221212 от Ravshanbekovna 09.12.2021 23:17

Question

Математика: Выражение: (1-〖cos〗^2 α)/(〖sin〗^2 α)+1/(〖sin〗^2 α*(1+〖tg〗^2 α))

Ravshanbekovna · Answer

(1-cos^2 α)/(sin^2 α)+1/(sin^2 α*(1+tg^2 α))

1-cos^2 α=sin^2α

1+tg^2 α=1/(cos^2a)

(1-cos^2 α)/(sin^2 α)+1/(sin^2 α*(1+tg^2 α))=sin^2α/(sin^2 α)+

+ 1/(sin^2 α*(1/cos^2a)=1+cos^2a/sin^2 α=1+ctg^2a=1/sin^2 a