|x+y-2|+x^2-2xy+y^2=0
|x+y-2|+(x-y)^2 = 0
{x+y-2 = 0
{x-y = 0
x=y
y+y-2 = 0
2y =2
y=1
Пошаговое объяснение:
(1+x^4)dy-2x(^2)ydx=0 y=4 x=-1
(1 + (-1)^4) x d x 4 - 2 x (-1)^2 x 4 x d x (-1) = 0
8d + 8d = 0
16d = 0
