ответ:sin4x+sin(π/2-4x)=0
sin4x+sin(π/2-4x)=02sinπ/4cos(4x-π/4)=0
sin4x+sin(π/2-4x)=02sinπ/4cos(4x-π/4)=0cos(4x-π/4)=0
sin4x+sin(π/2-4x)=02sinπ/4cos(4x-π/4)=0cos(4x-π/4)=04x-π/4=π/2+πn
sin4x+sin(π/2-4x)=02sinπ/4cos(4x-π/4)=0cos(4x-π/4)=04x-π/4=π/2+πn4x=π/4+π/2+πn=3π/4+πn
sin4x+sin(π/2-4x)=02sinπ/4cos(4x-π/4)=0cos(4x-π/4)=04x-π/4=π/2+πn4x=π/4+π/2+πn=3π/4+πnx=3π/16+πn/4
