(7a+3,5b+21) • (2,1c+17d+11,5)и (2x+3,2y+7)•(14x+7y+2,1) - вопрос №13598258735212117115232714721 от danilfkr 26.08.2021 20:37

Question

Математика: (7a+3,5b+21) • (2,1c+17d+11,5)и (2x+3,2y+7)•(14x+7y+2,1)​

danilfkr · Answer

(7a+3,5b+21) • (2,1c+17d+11,5) = 14,7ac + 119ad + 80,5а + 7,35bc + 59,5bd + 40,25b + 44,1c + 357d + 241,5(2x+3,2y+7) • (14x+7y+2,1) = 28x^2 + 58,8xy + 102,2x + 22,4y^2 + 55,72y + 14,7...

(7a+3,5b+21) • (2,1c+17d+11,5)и (2x+3,2y+7)•(14x+7y+2,1)​

(7a+3,5b+21) • (2,1c+17d+11,5)
и
(2x+3,2y+7)•(14x+7y+2,1)