x=0
Пошаговое объяснение:
log₅(5-x)=log₅(1-2x)+1
(log(5-x))/log5 = (log(1-2x))/log5 + 1
-1 - (log(1-2x))/log5 + (log(5-x))/log5 = 0
- (log5+log(1-2x)-log(5-x))/log5 = 0
log5+log(1-2x)-log(5-x)=0
log(5(1-2x)/5-x)=0
(5(1-2x)/(5-x)=0
5(1-2x)=5-x
5-10x=5-x
-10x+x=5-5
-9x=0
x=0
ОДЗ: 
Проверка:
ответ: {0}
